(y^2-4y-5)/(y^2-2y-15)

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Solution for (y^2-4y-5)/(y^2-2y-15) equation:


D( y )

y^2-(2*y)-15 = 0

y^2-(2*y)-15 = 0

y^2-(2*y)-15 = 0

y^2-2*y-15 = 0

y^2-2*y-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

y = (64^(1/2)+2)/(1*2) or y = (2-64^(1/2))/(1*2)

y = 5 or y = -3

y in (-oo:-3) U (-3:5) U (5:+oo)

(y^2-(4*y)-5)/(y^2-(2*y)-15) = 0

(y^2-4*y-5)/(y^2-2*y-15) = 0

y^2-4*y-5 = 0

y^2-4*y-5 = 0

DELTA = (-4)^2-(-5*1*4)

DELTA = 36

DELTA > 0

y = (36^(1/2)+4)/(1*2) or y = (4-36^(1/2))/(1*2)

y = 5 or y = -1

(y+1)*(y-5) = 0

y^2-2*y-15 = 0

y^2-2*y-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

y = (64^(1/2)+2)/(1*2) or y = (2-64^(1/2))/(1*2)

y = 5 or y = -3

(y+3)*(y-5) = 0

((y+1)*(y-5))/((y+3)*(y-5)) = 0

( y+1 )

y+1 = 0 // - 1

y = -1

( y-5 )

y-5 = 0 // + 5

y = 5

y in { 5}

y = -1

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